At 6 a.m., Jack and Ethan left Park U and drove towards Park V at average speeds of 98 km/h and 54 km/h respectively. Upon reaching Park V, Jack rested for 3 hours. He then headed back for Park U at an average speed of 98 km/h along the same route. Jack and Ethan met each other on their way at 12 noon.
- How far had Jack covered when he met Ethan on the way?
- How far apart were the two parks?
(a)
Time taken by Ethan = 6 h
Time taken by Jack = 6 - 3 = 3 h
Distance covered by Jack when he met Ethan
= 3 x 98
= 294 km
(b)
Distance travelled by Ethan
= 6 x 54
= 324 km
Distance of the two parks
= (294 + 324) ÷ 2
= 618 ÷ 2
= 309 km
Answer(s): (a) 294 km; (b) 309 km