At 9 a.m., Reggie and Justin left Park S and drove towards Park T at average speeds of 76 km/h and 59 km/h respectively. Upon reaching Park T, Reggie rested for 3 hours. He then headed back for Park S at an average speed of 76 km/h along the same route. Reggie and Justin met each other on their way at 1 p.m.
- How far had Reggie covered when he met Justin on the way?
- How far apart were the two parks?
(a)
Time taken by Justin = 4 h
Time taken by Reggie = 4 - 3 = 1 h
Distance covered by Reggie when he met Justin
= 1 x 76
= 76 km
(b)
Distance travelled by Justin
= 4 x 59
= 236 km
Distance of the two parks
= (76 + 236) ÷ 2
= 312 ÷ 2
= 156 km
Answer(s): (a) 76 km; (b) 156 km