At 7 a.m., Xavier and Mark left Park A and drove towards Park B at average speeds of 99 km/h and 57 km/h respectively. Upon reaching Park B, Xavier rested for 2 hours. He then headed back for Park A at an average speed of 99 km/h along the same route. Xavier and Mark met each other on their way at 12 noon.
- How far had Xavier covered when he met Mark on the way?
- How far apart were the two parks?
(a)
Time taken by Mark = 5 h
Time taken by Xavier = 5 - 2 = 3 h
Distance covered by Xavier when he met Mark
= 3 x 99
= 297 km
(b)
Distance travelled by Mark
= 5 x 57
= 285 km
Distance of the two parks
= (297 + 285) ÷ 2
= 582 ÷ 2
= 291 km
Answer(s): (a) 297 km; (b) 291 km
