At 7 a.m., Luis and Jack left Park K and drove towards Park L at average speeds of 88 km/h and 56 km/h respectively. Upon reaching Park L, Luis rested for 2 hours. He then headed back for Park K at an average speed of 88 km/h along the same route. Luis and Jack met each other on their way at 12 noon.
- How far had Luis covered when he met Jack on the way?
- How far apart were the two parks?
(a)
Time taken by Jack = 5 h
Time taken by Luis = 5 - 2 = 3 h
Distance covered by Luis when he met Jack
= 3 x 88
= 264 km
(b)
Distance travelled by Jack
= 5 x 56
= 280 km
Distance of the two parks
= (264 + 280) ÷ 2
= 544 ÷ 2
= 272 km
Answer(s): (a) 264 km; (b) 272 km
