At 6 a.m., Mark and Reggie left Park D and drove towards Park E at average speeds of 90 km/h and 52 km/h respectively. Upon reaching Park E, Mark rested for 2 hours. He then headed back for Park D at an average speed of 90 km/h along the same route. Mark and Reggie met each other on their way at 12 noon.
- How far had Mark covered when he met Reggie on the way?
- How far apart were the two parks?
(a)
Time taken by Reggie = 6 h
Time taken by Mark = 6 - 2 = 4 h
Distance covered by Mark when he met Reggie
= 4 x 90
= 360 km
(b)
Distance travelled by Reggie
= 6 x 52
= 312 km
Distance of the two parks
= (360 + 312) ÷ 2
= 672 ÷ 2
= 336 km
Answer(s): (a) 360 km; (b) 336 km