At 6 a.m., Eric and Charlie left Park U and drove towards Park V at average speeds of 100 km/h and 62 km/h respectively. Upon reaching Park V, Eric rested for 2 hours. He then headed back for Park U at an average speed of 100 km/h along the same route. Eric and Charlie met each other on their way at 12 noon.
- How far had Eric covered when he met Charlie on the way?
- How far apart were the two parks?
(a)
Time taken by Charlie = 6 h
Time taken by Eric = 6 - 2 = 4 h
Distance covered by Eric when he met Charlie
= 4 x 100
= 400 km
(b)
Distance travelled by Charlie
= 6 x 62
= 372 km
Distance of the two parks
= (400 + 372) ÷ 2
= 772 ÷ 2
= 386 km
Answer(s): (a) 400 km; (b) 386 km