At 6 a.m., Oscar and Luis left Park U and drove towards Park V at average speeds of 88 km/h and 64 km/h respectively. Upon reaching Park V, Oscar rested for 3 hours. He then headed back for Park U at an average speed of 88 km/h along the same route. Oscar and Luis met each other on their way at 12 noon.
- How far had Oscar covered when he met Luis on the way?
- How far apart were the two parks?
(a)
Time taken by Luis = 6 h
Time taken by Oscar = 6 - 3 = 3 h
Distance covered by Oscar when he met Luis
= 3 x 88
= 264 km
(b)
Distance travelled by Luis
= 6 x 64
= 384 km
Distance of the two parks
= (264 + 384) ÷ 2
= 648 ÷ 2
= 324 km
Answer(s): (a) 264 km; (b) 324 km