At 6 a.m., Jenson and Reggie left Park F and drove towards Park G at average speeds of 88 km/h and 55 km/h respectively. Upon reaching Park G, Jenson rested for 2 hours. He then headed back for Park F at an average speed of 88 km/h along the same route. Jenson and Reggie met each other on their way at 2 p.m.
- How far had Jenson covered when he met Reggie on the way?
- How far apart were the two parks?
(a)
Time taken by Reggie = 8 h
Time taken by Jenson = 8 - 2 = 6 h
Distance covered by Jenson when he met Reggie
= 6 x 88
= 528 km
(b)
Distance travelled by Reggie
= 8 x 55
= 440 km
Distance of the two parks
= (528 + 440) ÷ 2
= 968 ÷ 2
= 484 km
Answer(s): (a) 528 km; (b) 484 km