At 6 a.m., Vaidev and Seth left Park X and drove towards Park Y at average speeds of 92 km/h and 64 km/h respectively. Upon reaching Park Y, Vaidev rested for 2 hours. He then headed back for Park X at an average speed of 92 km/h along the same route. Vaidev and Seth met each other on their way at 12 noon.
- How far had Vaidev covered when he met Seth on the way?
- How far apart were the two parks?
(a)
Time taken by Seth = 6 h
Time taken by Vaidev = 6 - 2 = 4 h
Distance covered by Vaidev when he met Seth
= 4 x 92
= 368 km
(b)
Distance travelled by Seth
= 6 x 64
= 384 km
Distance of the two parks
= (368 + 384) ÷ 2
= 752 ÷ 2
= 376 km
Answer(s): (a) 368 km; (b) 376 km