At 5 a.m., Gabriel and Bobby left Park A and drove towards Park B at average speeds of 96 km/h and 64 km/h respectively. Upon reaching Park B, Gabriel rested for 3 hours. He then headed back for Park A at an average speed of 96 km/h along the same route. Gabriel and Bobby met each other on their way at 2 p.m.
- How far had Gabriel covered when he met Bobby on the way?
- How far apart were the two parks?
(a)
Time taken by Bobby = 9 h
Time taken by Gabriel = 9 - 3 = 6 h
Distance covered by Gabriel when he met Bobby
= 6 x 96
= 576 km
(b)
Distance travelled by Bobby
= 9 x 64
= 576 km
Distance of the two parks
= (576 + 576) ÷ 2
= 1152 ÷ 2
= 576 km
Answer(s): (a) 576 km; (b) 576 km