Xylia and Peter started running together along a cross country track. When Peter completed the track in 38 minutes, Xylia had run only
13 of the track. Xylia’s average speed was 110 m/min slower than Peter’s.
- How long was the cross country track in m?
- Find Xylia’s average speed in m/min.
(a)
When Peter completed the track:
Peter's distance = 3 u
Xylia's distance = 1 u
Extra distance covered by Peter
= 3 u - 1 u
= 2 u
2 u = 110 x 38
2 u = 4180
1 u = 4180 ÷ 2 = 2090
Distance of the cross country track
= 3 u
= 3 x 2090
= 6270 m
(b)
Peter's speed
= 6270 ÷ 38
= 165 m/min
Xylia's speed
= 165 - 110
= 55 m/min
Answer(s): (a) 6270 m; (b) 55 m/min