Linda and Pierre started running together along a cross country track. When Pierre completed the track in 50 minutes, Linda had run only
13 of the track. Linda’s average speed was 102 m/min slower than Pierre’s.
- How long was the cross country track in m?
- Find Linda’s average speed in m/min.
(a)
When Pierre completed the track:
Pierre's distance = 3 u
Linda's distance = 1 u
Extra distance covered by Pierre
= 3 u - 1 u
= 2 u
2 u = 102 x 50
2 u = 5100
1 u = 5100 ÷ 2 = 2550
Distance of the cross country track
= 3 u
= 3 x 2550
= 7650 m
(b)
Pierre's speed
= 7650 ÷ 50
= 153 m/min
Linda's speed
= 153 - 102
= 51 m/min
Answer(s): (a) 7650 m; (b) 51 m/min