Hilda and Jack started running together along a cross country track. When Jack completed the track in 28 minutes, Hilda had run only
59 of the track. Hilda’s average speed was 96 m/min slower than Jack’s.
- How long was the cross country track in m?
- Find Hilda’s average speed in m/min.
(a)
When Jack completed the track:
Jack's distance = 9 u
Hilda's distance = 5 u
Extra distance covered by Jack
= 9 u - 5 u
= 4 u
4 u = 96 x 28
4 u = 2688
1 u = 2688 ÷ 4 = 672
Distance of the cross country track
= 9 u
= 9 x 672
= 6048 m
(b)
Jack's speed
= 6048 ÷ 28
= 216 m/min
Hilda's speed
= 216 - 96
= 120 m/min
Answer(s): (a) 6048 m; (b) 120 m/min