Jaslyn and Howard started running together along a cross country track. When Howard completed the track in 46 minutes, Jaslyn had run only
38 of the track. Jaslyn’s average speed was 115 m/min slower than Howard’s.
- How long was the cross country track in m?
- Find Jaslyn’s average speed in m/min.
(a)
When Howard completed the track:
Howard's distance = 8 u
Jaslyn's distance = 3 u
Extra distance covered by Howard
= 8 u - 3 u
= 5 u
5 u = 115 x 46
5 u = 5290
1 u = 5290 ÷ 5 = 1058
Distance of the cross country track
= 8 u
= 8 x 1058
= 8464 m
(b)
Howard's speed
= 8464 ÷ 46
= 184 m/min
Jaslyn's speed
= 184 - 115
= 69 m/min
Answer(s): (a) 8464 m; (b) 69 m/min