Dana and Fred started running together along a cross country track. When Fred completed the track in 24 minutes, Dana had run only
49 of the track. Dana’s average speed was 110 m/min slower than Fred’s.
- How long was the cross country track in m?
- Find Dana’s average speed in m/min.
(a)
When Fred completed the track:
Fred's distance = 9 u
Dana's distance = 4 u
Extra distance covered by Fred
= 9 u - 4 u
= 5 u
5 u = 110 x 24
5 u = 2640
1 u = 2640 ÷ 5 = 528
Distance of the cross country track
= 9 u
= 9 x 528
= 4752 m
(b)
Fred's speed
= 4752 ÷ 24
= 198 m/min
Dana's speed
= 198 - 110
= 88 m/min
Answer(s): (a) 4752 m; (b) 88 m/min