Hilda and Peter started running together along a cross country track. When Peter completed the track in 46 minutes, Hilda had run only
35 of the track. Hilda’s average speed was 98 m/min slower than Peter’s.
- How long was the cross country track in m?
- Find Hilda’s average speed in m/min.
(a)
When Peter completed the track:
Peter's distance = 5 u
Hilda's distance = 3 u
Extra distance covered by Peter
= 5 u - 3 u
= 2 u
2 u = 98 x 46
2 u = 4508
1 u = 4508 ÷ 2 = 2254
Distance of the cross country track
= 5 u
= 5 x 2254
= 11270 m
(b)
Peter's speed
= 11270 ÷ 46
= 245 m/min
Hilda's speed
= 245 - 98
= 147 m/min
Answer(s): (a) 11270 m; (b) 147 m/min