Fred took 13 min to cycle from his home to a cafe for his morning exercise. After the exercise, he took 52 min to walk the same route home. The difference between his cycling and walking speed was 45 km/h. How far was Fred’s home from the cafe?
52 : 13
4 : 1

Walking speed : Cycling speed 
1 : 4 

The distance between Joe's home and the park was the same.

The travel time is inversely related to the speed.
When speed increases, the travel time decreases.

Difference in the the walking speed and cycling speed
= 4 u - 1 u
= 3 u

3 u = 45

1 u = 45 ÷ 3 = 15

Fred's walking speed = 15 km/h

60 min = 1 h
1 min = ¹₆₀ h
52 min = ⁵²₆₀ h = ¹³₁₅ h

Distance between Fred's home and the cafe
= ¹³₁₅ x 15 
= 13 km

Answer(s): 13 km