Howard took 14 min to cycle from his home to a church for his morning exercise. After the exercise, he took 56 min to walk the same route home. The difference between his cycling and walking speed was 45 km/h. How far was Howard’s home from the church?
56 : 14
4 : 1

Walking speed : Cycling speed 
1 : 4 

The distance between Joe's home and the park was the same.

The travel time is inversely related to the speed.
When speed increases, the travel time decreases.

Difference in the the walking speed and cycling speed
= 4 u - 1 u
= 3 u

3 u = 45

1 u = 45 ÷ 3 = 15

Howard's walking speed = 15 km/h

60 min = 1 h
1 min = ¹₆₀ h
56 min = ⁵⁶₆₀ h = ¹⁴₁₅ h

Distance between Howard's home and the church
= ¹⁴₁₅ x 15 
= 14 km

Answer(s): 14 km