Wesley took 10 min to cycle from his home to a playground for his morning exercise. After the exercise, he took 50 min to walk the same route home. The difference between his cycling and walking speed was 48 km/h. How far was Wesley’s home from the playground?
50 : 10
5 : 1

Walking speed : Cycling speed 
1 : 5 

The distance between Joe's home and the park was the same.

The travel time is inversely related to the speed.
When speed increases, the travel time decreases.

Difference in the the walking speed and cycling speed
= 5 u - 1 u
= 4 u

4 u = 48

1 u = 48 ÷ 4 = 12

Wesley's walking speed = 12 km/h

60 min = 1 h
1 min = ¹₆₀ h
50 min = ⁵⁰₆₀ h = ⁵₆ h

Distance between Wesley's home and the playground
= ⁵₆ x 12 
= 10 km

Answer(s): 10 km