Seth took 15 min to cycle from his home to a florist for his morning exercise. After the exercise, he took 48 min to walk the same route home. The difference between his cycling and walking speed was 55 km/h. How far was Seth’s home from the florist?
48 : 15
16 : 5

Walking speed : Cycling speed 
5 : 16 

The distance between Joe's home and the park was the same.

The travel time is inversely related to the speed.
When speed increases, the travel time decreases.

Difference in the the walking speed and cycling speed
= 16 u - 5 u
= 11 u

11 u = 55

1 u = 55 ÷ 11 = 5

Seth's walking speed = 5 km/h

60 min = 1 h
1 min = ¹₆₀ h
48 min = ⁴⁸₆₀ h = ⁴₅ h

Distance between Seth's home and the florist
= ⁴₅ x 5 
= 4 km

Answer(s): 4 km