Yoko and Jack started cycling at uniform speeds from the same place in opposite direction round 1200 m forest trail. Yoko took 40 seconds to complete each round while Jack took 60 seconds.
- Find the distance covered per second by Yoko in m.
- Find the distance covered per second by Jack in m.
- When the two cyclists next met again at the starting point, how far would Yoko have covered? Express the answer in km.
(a)
Distance covered by Yoko per second
= 1200 ÷ 40
= 30 m
(b)
Distance covered by Jack per second
= 1200 ÷ 60
= 20 m
(c)
LCM of 40 and 60 = 120
Time taken for Yoko to travel and meet Jack at the starting point = 120 s
Number of rounds covered by Yoko in 120 s
= 120 ÷ 40
= 3
Distance that Yoko travelled to meet again
= 3 x 1200
= 3600 m
1000 m = 1 km
3600 m = 3.6 km
Answer(s): (a) 30 m; (b) 20 m; (c) 3.6 km