Roshel and Eric started cycling at uniform speeds from the same place in opposite direction round 1080 m forest trail. Roshel took 45 seconds to complete each round while Eric took 54 seconds.
- Find the distance covered per second by Roshel in m.
- Find the distance covered per second by Eric in m.
- When the two cyclists next met again at the starting point, how far would Roshel have covered? Express the answer in km.
(a)
Distance covered by Roshel per second
= 1080 ÷ 45
= 24 m
(b)
Distance covered by Eric per second
= 1080 ÷ 54
= 20 m
(c)
LCM of 45 and 54 = 270
Time taken for Roshel to travel and meet Eric at the starting point = 270 s
Number of rounds covered by Roshel in 270 s
= 270 ÷ 45
= 6
Distance that Roshel travelled to meet again
= 6 x 1080
= 6480 m
1000 m = 1 km
6480 m = 6.48 km
Answer(s): (a) 24 m; (b) 20 m; (c) 6.48 km