Jean and Neave started cycling at uniform speeds from the same place in opposite direction round 960 m forest trail. Jean took 40 seconds to complete each round while Neave took 48 seconds.
- Find the distance covered per second by Jean in m.
- Find the distance covered per second by Neave in m.
- When the two cyclists next met again at the starting point, how far would Jean have covered? Express the answer in km.
(a)
Distance covered by Jean per second
= 960 ÷ 40
= 24 m
(b)
Distance covered by Neave per second
= 960 ÷ 48
= 20 m
(c)
LCM of 40 and 48 = 240
Time taken for Jean to travel and meet Neave at the starting point = 240 s
Number of rounds covered by Jean in 240 s
= 240 ÷ 40
= 6
Distance that Jean travelled to meet again
= 6 x 960
= 5760 m
1000 m = 1 km
5760 m = 5.76 km
Answer(s): (a) 24 m; (b) 20 m; (c) 5.76 km