Linda and Vincent started cycling at uniform speeds from the same place in opposite direction round 980 m forest trail. Linda took 49 seconds to complete each round while Vincent took 70 seconds.
- Find the distance covered per second by Linda in m.
- Find the distance covered per second by Vincent in m.
- When the two cyclists next met again at the starting point, how far would Linda have covered? Express the answer in km.
(a)
Distance covered by Linda per second
= 980 ÷ 49
= 20 m
(b)
Distance covered by Vincent per second
= 980 ÷ 70
= 14 m
(c)
LCM of 49 and 70 = 490
Time taken for Linda to travel and meet Vincent at the starting point = 490 s
Number of rounds covered by Linda in 490 s
= 490 ÷ 49
= 10
Distance that Linda travelled to meet again
= 10 x 980
= 9800 m
1000 m = 1 km
9800 m = 9.8 km
Answer(s): (a) 20 m; (b) 14 m; (c) 9.8 km