Betty and Japheth started cycling at uniform speeds from the same place in opposite direction round 1080 m forest trail. Betty took 40 seconds to complete each round while Japheth took 60 seconds.
- Find the distance covered per second by Betty in m.
- Find the distance covered per second by Japheth in m.
- When the two cyclists next met again at the starting point, how far would Betty have covered? Express the answer in km.
(a)
Distance covered by Betty per second
= 1080 ÷ 40
= 27 m
(b)
Distance covered by Japheth per second
= 1080 ÷ 60
= 18 m
(c)
LCM of 40 and 60 = 120
Time taken for Betty to travel and meet Japheth at the starting point = 120 s
Number of rounds covered by Betty in 120 s
= 120 ÷ 40
= 3
Distance that Betty travelled to meet again
= 3 x 1080
= 3240 m
1000 m = 1 km
3240 m = 3.24 km
Answer(s): (a) 27 m; (b) 18 m; (c) 3.24 km