Ivory and Jack started cycling at uniform speeds from the same place in opposite direction round 1120 m forest trail. Ivory took 40 seconds to complete each round while Jack took 56 seconds.
- Find the distance covered per second by Ivory in m.
- Find the distance covered per second by Jack in m.
- When the two cyclists next met again at the starting point, how far would Ivory have covered? Express the answer in km.
(a)
Distance covered by Ivory per second
= 1120 ÷ 40
= 28 m
(b)
Distance covered by Jack per second
= 1120 ÷ 56
= 20 m
(c)
LCM of 40 and 56 = 280
Time taken for Ivory to travel and meet Jack at the starting point = 280 s
Number of rounds covered by Ivory in 280 s
= 280 ÷ 40
= 7
Distance that Ivory travelled to meet again
= 7 x 1120
= 7840 m
1000 m = 1 km
7840 m = 7.84 km
Answer(s): (a) 28 m; (b) 20 m; (c) 7.84 km