Jaslyn and Seth started cycling at uniform speeds from the same place in opposite direction round 1050 m forest trail. Jaslyn took 42 seconds to complete each round while Seth took 70 seconds.
- Find the distance covered per second by Jaslyn in m.
- Find the distance covered per second by Seth in m.
- When the two cyclists next met again at the starting point, how far would Jaslyn have covered? Express the answer in km.
(a)
Distance covered by Jaslyn per second
= 1050 ÷ 42
= 25 m
(b)
Distance covered by Seth per second
= 1050 ÷ 70
= 15 m
(c)
LCM of 42 and 70 = 210
Time taken for Jaslyn to travel and meet Seth at the starting point = 210 s
Number of rounds covered by Jaslyn in 210 s
= 210 ÷ 42
= 5
Distance that Jaslyn travelled to meet again
= 5 x 1050
= 5250 m
1000 m = 1 km
5250 m = 5.25 km
Answer(s): (a) 25 m; (b) 15 m; (c) 5.25 km