Dana and Tim started cycling at uniform speeds from the same place in opposite direction round 840 m forest trail. Dana took 42 seconds to complete each round while Tim took 56 seconds.
- Find the distance covered per second by Dana in m.
- Find the distance covered per second by Tim in m.
- When the two cyclists next met again at the starting point, how far would Dana have covered? Express the answer in km.
(a)
Distance covered by Dana per second
= 840 ÷ 42
= 20 m
(b)
Distance covered by Tim per second
= 840 ÷ 56
= 15 m
(c)
LCM of 42 and 56 = 168
Time taken for Dana to travel and meet Tim at the starting point = 168 s
Number of rounds covered by Dana in 168 s
= 168 ÷ 42
= 4
Distance that Dana travelled to meet again
= 4 x 840
= 3360 m
1000 m = 1 km
3360 m = 3.36 km
Answer(s): (a) 20 m; (b) 15 m; (c) 3.36 km