Shannon and Jack started cycling at uniform speeds from the same place in opposite direction round 840 m forest trail. Shannon took 56 seconds to complete each round while Jack took 70 seconds.
- Find the distance covered per second by Shannon in m.
- Find the distance covered per second by Jack in m.
- When the two cyclists next met again at the starting point, how far would Shannon have covered? Express the answer in km.
(a)
Distance covered by Shannon per second
= 840 ÷ 56
= 15 m
(b)
Distance covered by Jack per second
= 840 ÷ 70
= 12 m
(c)
LCM of 56 and 70 = 280
Time taken for Shannon to travel and meet Jack at the starting point = 280 s
Number of rounds covered by Shannon in 280 s
= 280 ÷ 56
= 5
Distance that Shannon travelled to meet again
= 5 x 840
= 4200 m
1000 m = 1 km
4200 m = 4.2 km
Answer(s): (a) 15 m; (b) 12 m; (c) 4.2 km