Tina and Paul started cycling at uniform speeds from the same place in opposite direction round 900 m forest trail. Tina took 45 seconds to complete each round while Paul took 50 seconds.
- Find the distance covered per second by Tina in m.
- Find the distance covered per second by Paul in m.
- When the two cyclists next met again at the starting point, how far would Tina have covered? Express the answer in km.
(a)
Distance covered by Tina per second
= 900 ÷ 45
= 20 m
(b)
Distance covered by Paul per second
= 900 ÷ 50
= 18 m
(c)
LCM of 45 and 50 = 450
Time taken for Tina to travel and meet Paul at the starting point = 450 s
Number of rounds covered by Tina in 450 s
= 450 ÷ 45
= 10
Distance that Tina travelled to meet again
= 10 x 900
= 9000 m
1000 m = 1 km
9000 m = 9 km
Answer(s): (a) 20 m; (b) 18 m; (c) 9 km