Linda and Wesley started cycling at uniform speeds from the same place in opposite direction round 900 m forest trail. Linda took 50 seconds to complete each round while Wesley took 60 seconds.
- Find the distance covered per second by Linda in m.
- Find the distance covered per second by Wesley in m.
- When the two cyclists next met again at the starting point, how far would Linda have covered? Express the answer in km.
(a)
Distance covered by Linda per second
= 900 ÷ 50
= 18 m
(b)
Distance covered by Wesley per second
= 900 ÷ 60
= 15 m
(c)
LCM of 50 and 60 = 300
Time taken for Linda to travel and meet Wesley at the starting point = 300 s
Number of rounds covered by Linda in 300 s
= 300 ÷ 50
= 6
Distance that Linda travelled to meet again
= 6 x 900
= 5400 m
1000 m = 1 km
5400 m = 5.4 km
Answer(s): (a) 18 m; (b) 15 m; (c) 5.4 km