Jean and Simon started cycling at uniform speeds from the same place in opposite direction round 1020 m forest trail. Jean took 51 seconds to complete each round while Simon took 68 seconds.
- Find the distance covered per second by Jean in m.
- Find the distance covered per second by Simon in m.
- When the two cyclists next met again at the starting point, how far would Jean have covered? Express the answer in km.
(a)
Distance covered by Jean per second
= 1020 ÷ 51
= 20 m
(b)
Distance covered by Simon per second
= 1020 ÷ 68
= 15 m
(c)
LCM of 51 and 68 = 204
Time taken for Jean to travel and meet Simon at the starting point = 204 s
Number of rounds covered by Jean in 204 s
= 204 ÷ 51
= 4
Distance that Jean travelled to meet again
= 4 x 1020
= 4080 m
1000 m = 1 km
4080 m = 4.08 km
Answer(s): (a) 20 m; (b) 15 m; (c) 4.08 km