Raeann and Perry started cycling at uniform speeds from the same place in opposite direction round 960 m forest trail. Raeann took 48 seconds to complete each round while Perry took 64 seconds.
- Find the distance covered per second by Raeann in m.
- Find the distance covered per second by Perry in m.
- When the two cyclists next met again at the starting point, how far would Raeann have covered? Express the answer in km.
(a)
Distance covered by Raeann per second
= 960 ÷ 48
= 20 m
(b)
Distance covered by Perry per second
= 960 ÷ 64
= 15 m
(c)
LCM of 48 and 64 = 192
Time taken for Raeann to travel and meet Perry at the starting point = 192 s
Number of rounds covered by Raeann in 192 s
= 192 ÷ 48
= 4
Distance that Raeann travelled to meet again
= 4 x 960
= 3840 m
1000 m = 1 km
3840 m = 3.84 km
Answer(s): (a) 20 m; (b) 15 m; (c) 3.84 km