Esther and Fred started cycling at uniform speeds from the same place in opposite direction round 990 m forest trail. Esther took 55 seconds to complete each round while Fred took 66 seconds.
- Find the distance covered per second by Esther in m.
- Find the distance covered per second by Fred in m.
- When the two cyclists next met again at the starting point, how far would Esther have covered? Express the answer in km.
(a)
Distance covered by Esther per second
= 990 ÷ 55
= 18 m
(b)
Distance covered by Fred per second
= 990 ÷ 66
= 15 m
(c)
LCM of 55 and 66 = 330
Time taken for Esther to travel and meet Fred at the starting point = 330 s
Number of rounds covered by Esther in 330 s
= 330 ÷ 55
= 6
Distance that Esther travelled to meet again
= 6 x 990
= 5940 m
1000 m = 1 km
5940 m = 5.94 km
Answer(s): (a) 18 m; (b) 15 m; (c) 5.94 km