Raeann and Jenson started cycling at uniform speeds from the same place in opposite direction round 840 m forest trail. Raeann took 42 seconds to complete each round while Jenson took 60 seconds.
- Find the distance covered per second by Raeann in m.
- Find the distance covered per second by Jenson in m.
- When the two cyclists next met again at the starting point, how far would Raeann have covered? Express the answer in km.
(a)
Distance covered by Raeann per second
= 840 ÷ 42
= 20 m
(b)
Distance covered by Jenson per second
= 840 ÷ 60
= 14 m
(c)
LCM of 42 and 60 = 420
Time taken for Raeann to travel and meet Jenson at the starting point = 420 s
Number of rounds covered by Raeann in 420 s
= 420 ÷ 42
= 10
Distance that Raeann travelled to meet again
= 10 x 840
= 8400 m
1000 m = 1 km
8400 m = 8.4 km
Answer(s): (a) 20 m; (b) 14 m; (c) 8.4 km