Jaslyn and Sean started cycling at uniform speeds from the same place in opposite direction round 1100 m forest trail. Jaslyn took 44 seconds to complete each round while Sean took 55 seconds.
- Find the distance covered per second by Jaslyn in m.
- Find the distance covered per second by Sean in m.
- When the two cyclists next met again at the starting point, how far would Jaslyn have covered? Express the answer in km.
(a)
Distance covered by Jaslyn per second
= 1100 ÷ 44
= 25 m
(b)
Distance covered by Sean per second
= 1100 ÷ 55
= 20 m
(c)
LCM of 44 and 55 = 220
Time taken for Jaslyn to travel and meet Sean at the starting point = 220 s
Number of rounds covered by Jaslyn in 220 s
= 220 ÷ 44
= 5
Distance that Jaslyn travelled to meet again
= 5 x 1100
= 5500 m
1000 m = 1 km
5500 m = 5.5 km
Answer(s): (a) 25 m; (b) 20 m; (c) 5.5 km