Tina and Peter started cycling at uniform speeds from the same place in opposite direction round 840 m forest trail. Tina took 42 seconds to complete each round while Peter took 70 seconds.
- Find the distance covered per second by Tina in m.
- Find the distance covered per second by Peter in m.
- When the two cyclists next met again at the starting point, how far would Tina have covered? Express the answer in km.
(a)
Distance covered by Tina per second
= 840 ÷ 42
= 20 m
(b)
Distance covered by Peter per second
= 840 ÷ 70
= 12 m
(c)
LCM of 42 and 70 = 210
Time taken for Tina to travel and meet Peter at the starting point = 210 s
Number of rounds covered by Tina in 210 s
= 210 ÷ 42
= 5
Distance that Tina travelled to meet again
= 5 x 840
= 4200 m
1000 m = 1 km
4200 m = 4.2 km
Answer(s): (a) 20 m; (b) 12 m; (c) 4.2 km