Xylia and Oscar started cycling at uniform speeds from the same place in opposite direction round 990 m forest trail. Xylia took 45 seconds to complete each round while Oscar took 55 seconds.
- Find the distance covered per second by Xylia in m.
- Find the distance covered per second by Oscar in m.
- When the two cyclists next met again at the starting point, how far would Xylia have covered? Express the answer in km.
(a)
Distance covered by Xylia per second
= 990 ÷ 45
= 22 m
(b)
Distance covered by Oscar per second
= 990 ÷ 55
= 18 m
(c)
LCM of 45 and 55 = 495
Time taken for Xylia to travel and meet Oscar at the starting point = 495 s
Number of rounds covered by Xylia in 495 s
= 495 ÷ 45
= 11
Distance that Xylia travelled to meet again
= 11 x 990
= 10890 m
1000 m = 1 km
10890 m = 10.89 km
Answer(s): (a) 22 m; (b) 18 m; (c) 10.89 km