Tina and Michael started cycling at uniform speeds from the same place in opposite direction round 1050 m forest trail. Tina took 50 seconds to complete each round while Michael took 70 seconds.
- Find the distance covered per second by Tina in m.
- Find the distance covered per second by Michael in m.
- When the two cyclists next met again at the starting point, how far would Tina have covered? Express the answer in km.
(a)
Distance covered by Tina per second
= 1050 ÷ 50
= 21 m
(b)
Distance covered by Michael per second
= 1050 ÷ 70
= 15 m
(c)
LCM of 50 and 70 = 350
Time taken for Tina to travel and meet Michael at the starting point = 350 s
Number of rounds covered by Tina in 350 s
= 350 ÷ 50
= 7
Distance that Tina travelled to meet again
= 7 x 1050
= 7350 m
1000 m = 1 km
7350 m = 7.35 km
Answer(s): (a) 21 m; (b) 15 m; (c) 7.35 km