Yoko and David started cycling at uniform speeds from the same place in opposite direction round 1080 m forest trail. Yoko took 40 seconds to complete each round while David took 45 seconds.
- Find the distance covered per second by Yoko in m.
- Find the distance covered per second by David in m.
- When the two cyclists next met again at the starting point, how far would Yoko have covered? Express the answer in km.
(a)
Distance covered by Yoko per second
= 1080 ÷ 40
= 27 m
(b)
Distance covered by David per second
= 1080 ÷ 45
= 24 m
(c)
LCM of 40 and 45 = 360
Time taken for Yoko to travel and meet David at the starting point = 360 s
Number of rounds covered by Yoko in 360 s
= 360 ÷ 40
= 9
Distance that Yoko travelled to meet again
= 9 x 1080
= 9720 m
1000 m = 1 km
9720 m = 9.72 km
Answer(s): (a) 27 m; (b) 24 m; (c) 9.72 km