Cathy and Paul started cycling at uniform speeds from the same place in opposite direction round 840 m forest trail. Cathy took 60 seconds to complete each round while Paul took 70 seconds.
- Find the distance covered per second by Cathy in m.
- Find the distance covered per second by Paul in m.
- When the two cyclists next met again at the starting point, how far would Cathy have covered? Express the answer in km.
(a)
Distance covered by Cathy per second
= 840 ÷ 60
= 14 m
(b)
Distance covered by Paul per second
= 840 ÷ 70
= 12 m
(c)
LCM of 60 and 70 = 420
Time taken for Cathy to travel and meet Paul at the starting point = 420 s
Number of rounds covered by Cathy in 420 s
= 420 ÷ 60
= 7
Distance that Cathy travelled to meet again
= 7 x 840
= 5880 m
1000 m = 1 km
5880 m = 5.88 km
Answer(s): (a) 14 m; (b) 12 m; (c) 5.88 km