Usha and Tim started cycling at uniform speeds from the same place in opposite direction round 1120 m forest trail. Usha took 56 seconds to complete each round while Tim took 70 seconds.
- Find the distance covered per second by Usha in m.
- Find the distance covered per second by Tim in m.
- When the two cyclists next met again at the starting point, how far would Usha have covered? Express the answer in km.
(a)
Distance covered by Usha per second
= 1120 ÷ 56
= 20 m
(b)
Distance covered by Tim per second
= 1120 ÷ 70
= 16 m
(c)
LCM of 56 and 70 = 280
Time taken for Usha to travel and meet Tim at the starting point = 280 s
Number of rounds covered by Usha in 280 s
= 280 ÷ 56
= 5
Distance that Usha travelled to meet again
= 5 x 1120
= 5600 m
1000 m = 1 km
5600 m = 5.6 km
Answer(s): (a) 20 m; (b) 16 m; (c) 5.6 km