Raeann and Pierre started cycling at uniform speeds from the same place in opposite direction round 1120 m forest trail. Raeann took 40 seconds to complete each round while Pierre took 70 seconds.
- Find the distance covered per second by Raeann in m.
- Find the distance covered per second by Pierre in m.
- When the two cyclists next met again at the starting point, how far would Raeann have covered? Express the answer in km.
(a)
Distance covered by Raeann per second
= 1120 ÷ 40
= 28 m
(b)
Distance covered by Pierre per second
= 1120 ÷ 70
= 16 m
(c)
LCM of 40 and 70 = 280
Time taken for Raeann to travel and meet Pierre at the starting point = 280 s
Number of rounds covered by Raeann in 280 s
= 280 ÷ 40
= 7
Distance that Raeann travelled to meet again
= 7 x 1120
= 7840 m
1000 m = 1 km
7840 m = 7.84 km
Answer(s): (a) 28 m; (b) 16 m; (c) 7.84 km