Penelope and Xavier started off from the same place and drove at uniform speeds in the same direction round a 45 km circular racing track. Penelope completed each round in 50 minutes. Xavier took 60 minutes to complete each round.
- How far would Xavier be behind Penelope after 1 hour?
- How long after they started would it take Penelope to meet Xavier for the first time? Express your answer as a whole or mixed number in h.
(a)
60 min = 1 h
1 min =
160 h
50 min =
5060 h =
56 h
60 min =
6060 h = 1 h
Penelope's speed
= 45 ÷
56= 45 x
65= 54 km/h
Xavier's speed
= 45 ÷ 1
= 45 x
11= 45 km/h
Distance between Penelope and Xavier after 1 hour
= 54 - 45
= 9 km
(b)
LCM of 50 and 60 = 300
300 min =
30060 h = 5 h
Time needed for Penelope to meet Xavier for the first time = 5 h
Answer(s): (a) 9 km; (b) 5 h