At 12 25, Asher left Town U for Town V, driving at a speed of 64 km/h. At 15 25, Peter also left Town U for Town V driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 25, both of them passed a grocery store that was 192 km away from Town V. How many minutes earlier did Peter reach Town V than Asher?

Distance that Asher travelled
= 6 x 64
= 384 km

Distance between Town U and Town V
= 384 + 192
= 576 km

Since Peter passed the grocery store at the same time as Asher, it means that Peter travelled 384 km in 3 hours.

Peter's speed during the journey
= 384 ÷ 3
= 128 km/h

Duration that Peter took to reach Town V after passing the grocery store
= 192 ÷ 128
= 1.5 h

Duration that Asher took to reach Town V after passing the grocery store
= 192 ÷ 64
= 3 h

Difference between the time they took to reach Town V
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Peter reached Town V 90 minutes earlier than Asher.

Answer(s): 90 min