At 13 45, Justin left Town B for Town C, driving at a speed of 75 km/h. At 16 45, Neave also left Town B for Town C driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 45, both of them passed a farm that was 225 km away from Town C. How many minutes earlier did Neave reach Town C than Justin?
Duration that Justin travelled from 13 45 to 19 45 = 6 h
Distance that Justin travelled
= 6 x 75
= 450 km
Distance between Town B and Town C
= 450 + 225
= 675 km
Since Neave passed the farm at the same time as Justin, it means that Neave travelled 450 km in 3 hours.
Neave's speed during the journey
= 450 ÷ 3
= 150 km/h
Duration that Neave took to reach Town C after passing the farm
= 225 ÷ 150
= 1.5 h
Duration that Justin took to reach Town C after passing the farm
= 225 ÷ 75
= 3 h
Difference between the time they took to reach Town C
= 3 - 1.5
= 1.5 h
1 h = 60 min
1.5 h = 1.5 x 60 = 90 min
Neave reached Town C 90 minutes earlier than Justin.
Answer(s): 90 min
