At 14 10, Ryan left Town F for Town G, driving at a speed of 68 km/h. At 15 10, Charlie also left Town F for Town G driving at a certain speed. Both of them did not change their speed throughout the journey. At 19 10, both of them passed a boutique that was 136 km away from Town G. How many minutes earlier did Charlie reach Town G than Ryan?

Distance that Ryan travelled
= 5 x 68
= 340 km

Distance between Town F and Town G
= 340 + 136
= 476 km

Since Charlie passed the boutique at the same time as Ryan, it means that Charlie travelled 340 km in 4 hours.

Charlie's speed during the journey
= 340 ÷ 4
= 85 km/h

Duration that Charlie took to reach Town G after passing the boutique
= 136 ÷ 85
= 1.6 h

Duration that Ryan took to reach Town G after passing the boutique
= 136 ÷ 68
= 2 h

Difference between the time they took to reach Town G
= 2 - 1.6
= 0.4 h

1 h = 60 min
0.4 h = 0.4 x 60 = 24 min

Charlie reached Town G 24 minutes earlier than Ryan.

Answer(s): 24 min