At 12 10, Ryan left Town J for Town K, driving at a speed of 60 km/h. At 13 10, Reggie also left Town J for Town K driving at a certain speed. Both of them did not change their speed throughout the journey. At 16 10, both of them passed a park that was 120 km away from Town K. How many minutes earlier did Reggie reach Town K than Ryan?
Duration that Ryan travelled from 12 10 to 16 10 = 4 h
Distance that Ryan travelled
= 4 x 60
= 240 km
Distance between Town J and Town K
= 240 + 120
= 360 km
Since Reggie passed the park at the same time as Ryan, it means that Reggie travelled 240 km in 3 hours.
Reggie's speed during the journey
= 240 ÷ 3
= 80 km/h
Duration that Reggie took to reach Town K after passing the park
= 120 ÷ 80
= 1.5 h
Duration that Ryan took to reach Town K after passing the park
= 120 ÷ 60
= 2 h
Difference between the time they took to reach Town K
= 2 - 1.5
= 0.5 h
1 h = 60 min
0.5 h = 0.5 x 60 = 30 min
Reggie reached Town K 30 minutes earlier than Ryan.
Answer(s): 30 min