At 12 20, Jack left Town V for Town W, driving at a speed of 92 km/h. At 13 20, Eric also left Town V for Town W driving at a certain speed. Both of them did not change their speed throughout the journey. At 17 20, both of them passed a bakery that was 184 km away from Town W. How many minutes earlier did Eric reach Town W than Jack?
Duration that Jack travelled from 12 20 to 17 20 = 5 h
Distance that Jack travelled
= 5 x 92
= 460 km
Distance between Town V and Town W
= 460 + 184
= 644 km
Since Eric passed the bakery at the same time as Jack, it means that Eric travelled 460 km in 4 hours.
Eric's speed during the journey
= 460 ÷ 4
= 115 km/h
Duration that Eric took to reach Town W after passing the bakery
= 184 ÷ 115
= 1.6 h
Duration that Jack took to reach Town W after passing the bakery
= 184 ÷ 92
= 2 h
Difference between the time they took to reach Town W
= 2 - 1.6
= 0.4 h
1 h = 60 min
0.4 h = 0.4 x 60 = 24 min
Eric reached Town W 24 minutes earlier than Jack.
Answer(s): 24 min
