At 14 25, Ken left Town Y for Town Z, driving at a speed of 89 km/h. At 16 25, Howard also left Town Y for Town Z driving at a certain speed. Both of them did not change their speed throughout the journey. At 18 25, both of them passed a mosque that was 267 km away from Town Z. How many minutes earlier did Howard reach Town Z than Ken?

Distance that Ken travelled
= 4 x 89
= 356 km

Distance between Town Y and Town Z
= 356 + 267
= 623 km

Since Howard passed the mosque at the same time as Ken, it means that Howard travelled 356 km in 2 hours.

Howard's speed during the journey
= 356 ÷ 2
= 178 km/h

Duration that Howard took to reach Town Z after passing the mosque
= 267 ÷ 178
= 1.5 h

Duration that Ken took to reach Town Z after passing the mosque
= 267 ÷ 89
= 3 h

Difference between the time they took to reach Town Z
= 3 - 1.5
= 1.5 h

1 h = 60 min
1.5 h = 1.5 x 60 = 90 min

Howard reached Town Z 90 minutes earlier than Ken.

Answer(s): 90 min